ax square

 Solve the quadratic equation and find the value of x. Not just the answer, but with all steps and explain it.  

 axsquare+bx+c=0

Multiply both sides with 4a. by adding substracting or multiplying both sides of the equation makes no difference in the value of the equation..

4a(ax square)+ 4 abx+4ac=0 (4a)......1

4a square x square+4 abx + 4 ac= 0.....2 

as 4a into 0 is Zero

4a suare x square + 4 abx = -- 4 ac.........3

add (b square) both sides

4a square x square+ 4abx+b square = b suare--4 ac............4

4 a square x square+ 4 abx + b square = (2ax+b) whole square........5

(2ax +b ) whole suare = b square-- 4 ac...............6

Square rooting both sides

2 ax +b = square root of ( b square--4 ac ).....7

2 ax = --b plus or minus (b square --4 ac)...........8

x= --b plus or minus (b square --4 ac )/2 a..........9

problem solved.

Testing my memory...

(Corrected at the evening by 5.30 PM)

Sorry! committed a blunder from step ...4

Step4 should be (b square--4ac) but shown as (b square+4ac) till the step 9. Finally the answer is wrong.

1978 లో ఇలాగే ఒక లెక్కకి చివరగా ఆన్సరు --1 ఐతే 1 అని వేసేసేను. 90 మార్కులొచ్చినా జీవిత పరిక్ష తప్పింది, ఒక్క మార్కులో పోటీ పరిక్షలో సెలక్షన్ పోయింది.